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Browse through your entire collection, rating images and adding keywords that help you find what you’re looking for. Then back up the app on your cloud storage account using any one of the available options. How to download and install Lightroom Get to know the app Explore app features in depth Need help installing? Need help . A: My guess is that your subscription has expired. Once your subscription expires, Lightroom will not be available for you to download any more, and the license key will not work either. Also, make sure that you do not have any other subscription to Adobe products like Photoshop. You can read more about this in the Adobe help. If you are using the Mac version of Photoshop, you can sign up to the Creative Cloud for free, and that should solve the problem. Advertising Read more Zagreb (AFP) Croatia on Tuesday entered a joint administration with its southern neighbour Bosnia over their border dispute with Serbia following a plea from the European Union and NATO. Bosnia's government said the move had been taken to ensure better security and border protection, particularly in the northern part of the border region. "This step will provide for an enhanced security of both states," Bosnia said. Croatian authorities, who have long accused Serbia of providing support to Bosnian Serbs in the war, welcomed the move. "The joint administration will allow us to protect the state and also protect people," Croatian defence ministry spokesman Igor Lukšić told AFP. NATO said the deal should help "clarify the border between Bosnia and Croatia and... help to prevent the violation of the border" -- a reference to alleged violations by Bosnia's army. © 2017 AFPQ: Why is my SQL query not working? I want to UPDATE one table with data from another and I am having some problems. UPDATE users SET name= (SELECT username FROM users_loggedin WHERE id =2) WHERE id=2; I don't know why it won't work. This is my full code : $db = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME) or die("server misconfiguration"); $username = $_POST['username']; $id = $_POST['
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